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Another Physics question.
Apr 22 2004 09:53pm

(Jedi)Obi-JK
 - Student
(Jedi)Obi-JK
A bullet is fired from a gun, the path of the bullet is parrallel to ground. At the same height of the gun an identical bullet is dropped perpendicular to the ground, which which land on the ground 1st?

Details for the anal:

A path in the dierction of the bullet, is long enough for it to travel with nothing in its path, the ground stays perfectly level the entire time.

We are neglecting the the weight of the shell which will, still be on the bullet which was dropped and not on the the bullet which is fired.

If someone tried to be a smart ass, or super anal Ill add to this list of things to neglect / not think about / etc.
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Comments
Apr 25 2004 04:50pm

Bubu
 - Hubbub
 Bubu

lmao anal as in "anal retentive"... study freud :P
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Apr 25 2004 04:45pm

Bail Hope of Belouve
 - Student
 Bail Hope of Belouve

okay, I'm not english, so forgive me for saying something stupid (which I probably will...)

but what does the word 'anal' have to do with it? :confused:
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Apr 25 2004 03:20pm

o2b
 - Student
 o2b

JavaGuy's correct...the bullet (also called projectile or round) spins quite fast. This is to stabilize the round, otherwise it would be woefully inaccurate. As it spins, however, skin friction 'drags' the surrounding air with it. The result is much like a backspin shot in tennis, which makes the ball seem to 'float' a lot more than normal.
It does this by creating a higher pressure underneath than on top, thus creating a small amount of lift. Not enough to make it go upwards, but enough to delay the drop :) Which means, the fired round would hit later, but not my much.

However, if you were in a vacuum, then the spinning then means 3/8ths of f--k all and only acts to stabilise the round. So they'd both hit the ground at the same time.

As an aside...this spinning of the round brings in to effect the 'gyroscopic law of precession' - which makes a spinning object act independantly of the earths rotation, meaning that it moves according to space. For this reason, adjustable rifle sights (and some pistol I might add) actually move sideways when you extend the range!

Apr 25 2004 12:48pm

Lord Jaws
 - Student
 Lord Jaws

The force of the gun propels the fired bullet strictly horizontally. The only downward force is gravity, which acts equally on both bullets. Therefore they both hit the ground at the same time
But it depends on the distance the fired bullet is traveling. keep in mind that the earth is round, so since the fired bullet has farther to fall, it takes longer to hit the earth, so the dropped bullet hits the ground first.
:D took a time to think about this..
(and we assume that the bullit is dropped from the same hight of the fired bullet, not the gun ,and there is no wind, you could say a vacuum)
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Apr 25 2004 11:52am

Flash
 - Student
 Flash

Oh, didn't read that part. Whoops.:o

Apr 23 2004 04:33am

JavaGuy
 - Student
 JavaGuy

He said the ground stays level, so the curvature of the Earth is not a factor (hey, it's a thought experiment, so we're allowed to do that!).


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Apr 23 2004 02:20am

Flash
 - Student
 Flash

They will both land at the same time unless you take into effect other factors, such as if the shot bullet goes so far that the earth starts curving away from it. The drag of the air on the shot might also make the shot bullet hit the ground at a different time than the dropped bullet too.

This comment was edited by Flash on Apr 23 2004 02:25am.

Apr 23 2004 02:12am

JavaGuy
 - Student
 JavaGuy

An aside: A bullet spins as it is fired from a gun, due to rifling (a spiral groove running around the inside of the barrel). When you hear the crime lab guy on a cop show talk about a bullet being fired from a gun with a right-twist or a left-twist, I think that's what he means (anybody know for sure?). The reason for the spin is that if the bullet didn't spin, it would tumble, and its aerodynamics would consequently suck. When rifles first appeared they changed the nature of warfare because soldiers could now accurately shoot something many times the distance of what they could shoot with a musket, which just shot a ball with no particular aerodynamic design at all.

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Apr 23 2004 02:10am

Ancient
 - Ex-Student
 Ancient

Quote:
same time, assuming you ignore all forces but gravity, as thats the only thign it pulls both equaly and they both will hit the ground same time reguardless of how far they go sideways. right ?


Squbit is absolutly right here, this kind of conceptual question is quite common in the topic of projectile motion. In mechanical physics we can look at a projectile motion in separate vector, one "X"(horzontial direction) and the other one is "Y"(vertical direction). When we are trying to calculate the time require for the "shooting bullet" to fall, we will only consider the "Y" direction. After we took the integral of the gravitational acceleration, we will get Y=V<y0>t-(1/2)gt^2 which is exactly the same equation compare to the one dimensional equation.:D:D:D:D
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Apr 23 2004 01:22am

(Jedi)Obi-JK
 - Student
 (Jedi)Obi-JK

This was alot easier than JavaGuy's, I got another ill look up soon.
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-Steve (Obi)


Apr 22 2004 11:07pm

Gradius
 - Ex-Student
 Gradius

I would go with both hitting at the same time.
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Apr 22 2004 10:30pm

Johnnyrico
 - Student
 Johnnyrico

i'd say that the bullet that wasnt fired will fall first. When you shoot the bullet it flys at a fast speed so it will continue to move parallel to the ground until it will start to lose its "power"
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Apr 22 2004 10:21pm

Squibit
 - Student
 Squibit

same time, assuming you ignore all forces but gravity, as thats the only thign it pulls both equaly and they both will hit the ground same time reguardless of how far they go sideways. right ?
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